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14012043444121 is a prime number
BaseRepresentation
bin1100101111100110111011…
…0111110011111110011001
31211121112112101210022020111
43023321232313303332121
53314033131110202441
645445013251524321
72644223333055412
oct313715667637631
954545471708214
1014012043444121
11451252425a498
1216a3764bb96a1
137a843a0b9b48
14366287b58809
151947433a1081
hexcbe6edf3f99

14012043444121 has 2 divisors, whose sum is σ = 14012043444122. Its totient is φ = 14012043444120.

The previous prime is 14012043444089. The next prime is 14012043444149. The reversal of 14012043444121 is 12144434021041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9292352368896 + 4719691075225 = 3048336^2 + 2172485^2 .

It is a cyclic number.

It is not a de Polignac number, because 14012043444121 - 25 = 14012043444089 is a prime.

It is a super-2 number, since 2×140120434441212 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14012043448121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006021722060 + 7006021722061.

It is an arithmetic number, because the mean of its divisors is an integer number (7006021722061).

Almost surely, 214012043444121 is an apocalyptic number.

It is an amenable number.

14012043444121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14012043444121 is an equidigital number, since it uses as much as digits as its factorization.

14012043444121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 14012043444121 its reverse (12144434021041), we get a palindrome (26156477465162).

The spelling of 14012043444121 in words is "fourteen trillion, twelve billion, forty-three million, four hundred forty-four thousand, one hundred twenty-one".