Search a number
-
+
140121051344401 is a prime number
BaseRepresentation
bin11111110111000001111001…
…011111011010111000010001
3200101010102220222200222111011
4133313001321133122320101
5121331220403121010101
61214002420005250521
741341261163526361
oct3767017137327021
9611112828628434
10140121051344401
1140713005598a36
1213870494703a41
13602548767123a
142685c761089a1
15112ed0b916751
hex7f70797dae11

140121051344401 has 2 divisors, whose sum is σ = 140121051344402. Its totient is φ = 140121051344400.

The previous prime is 140121051344311. The next prime is 140121051344489. The reversal of 140121051344401 is 104443150121041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99505093850176 + 40615957494225 = 9975224^2 + 6373065^2 .

It is a cyclic number.

It is not a de Polignac number, because 140121051344401 - 217 = 140121051213329 is a prime.

It is a super-2 number, since 2×1401210513444012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140121051314401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70060525672200 + 70060525672201.

It is an arithmetic number, because the mean of its divisors is an integer number (70060525672201).

Almost surely, 2140121051344401 is an apocalyptic number.

It is an amenable number.

140121051344401 is a deficient number, since it is larger than the sum of its proper divisors (1).

140121051344401 is an equidigital number, since it uses as much as digits as its factorization.

140121051344401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 31.

The spelling of 140121051344401 in words is "one hundred forty trillion, one hundred twenty-one billion, fifty-one million, three hundred forty-four thousand, four hundred one".