Base | Representation |
---|---|
bin | 1100101111100111001011… |
… | …1101011111010101100010 |
3 | 1211121112201011212101220021 |
4 | 3023321302331133111202 |
5 | 3314033301140310224 |
6 | 45445024142104054 |
7 | 2644225125120262 |
oct | 313716275372542 |
9 | 54545634771807 |
10 | 14012112041314 |
11 | 4512559a52592 |
12 | 16a3783b7b02a |
13 | 7a844b386cba |
14 | 366292cd37a2 |
15 | 1947494011e4 |
hex | cbe72f5f562 |
14012112041314 has 4 divisors (see below), whose sum is σ = 21018168061974. Its totient is φ = 7006056020656.
The previous prime is 14012112041309. The next prime is 14012112041329. The reversal of 14012112041314 is 41314021121041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12634932339225 + 1377179702089 = 3554565^2 + 1173533^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3503028010327 + ... + 3503028010330.
Almost surely, 214012112041314 is an apocalyptic number.
14012112041314 is a deficient number, since it is larger than the sum of its proper divisors (7006056020660).
14012112041314 is an equidigital number, since it uses as much as digits as its factorization.
14012112041314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7006056020659.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 14012112041314 its reverse (41314021121041), we get a palindrome (55326133162355).
The spelling of 14012112041314 in words is "fourteen trillion, twelve billion, one hundred twelve million, forty-one thousand, three hundred fourteen".
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