140121130440413 has 4 divisors (see below), whose sum is σ = 140168325165660. Its totient is φ = 140073935715168.

The previous prime is 140121130440391. The next prime is 140121130440493. The reversal of 140121130440413 is 314044031121041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13964137607044 + 126156992833369 = 3736862^2 + 11231963^2 .

It is a cyclic number.

It is not a de Polignac number, because 140121130440413 - 2³² = 140116835473117 is a prime.

It is a super-2 number, since 2×140121130440413² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140121130440493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23597358170 + ... + 23597364107.

It is an arithmetic number, because the mean of its divisors is an integer number (35042081291415).

Almost surely, 2^{140121130440413} is an apocalyptic number.

It is an amenable number.

140121130440413 is a deficient number, since it is larger than the sum of its proper divisors (47194725247).

140121130440413 is an equidigital number, since it uses as much as digits as its factorization.

140121130440413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47194725246.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 140121130440413 its reverse (314044031121041), we get a palindrome (454165161561454).

The spelling of 140121130440413 in words is "one hundred forty trillion, one hundred twenty-one billion, one hundred thirty million, four hundred forty thousand, four hundred thirteen".