Base | Representation |
---|---|
bin | 1000001001111111011… |
… | …1110001101000001011 |
3 | 111101200021200001001201 |
4 | 2002133313301220023 |
5 | 4243432003331021 |
6 | 144212030325031 |
7 | 13060222066111 |
oct | 2023767615013 |
9 | 441607601051 |
10 | 140121152011 |
11 | 54474812475 |
12 | 231a6359777 |
13 | 102a0a00389 |
14 | 6ad3767ab1 |
15 | 39a16a3591 |
hex | 209fdf1a0b |
140121152011 has 2 divisors, whose sum is σ = 140121152012. Its totient is φ = 140121152010.
The previous prime is 140121151913. The next prime is 140121152089. The reversal of 140121152011 is 110251121041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140121152011 - 235 = 105761413643 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 140121152011.
It is not a weakly prime, because it can be changed into another prime (140121152711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70060576005 + 70060576006.
It is an arithmetic number, because the mean of its divisors is an integer number (70060576006).
Almost surely, 2140121152011 is an apocalyptic number.
140121152011 is a deficient number, since it is larger than the sum of its proper divisors (1).
140121152011 is an equidigital number, since it uses as much as digits as its factorization.
140121152011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 140121152011 its reverse (110251121041), we get a palindrome (250372273052).
The spelling of 140121152011 in words is "one hundred forty billion, one hundred twenty-one million, one hundred fifty-two thousand, eleven".
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