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1401212412022 = 234912197164587
BaseRepresentation
bin10100011000111110110…
…001001010000001110110
311221221202220100201002211
4110120332301022001312
5140424140334141042
62551412540524034
7203143230661663
oct24307661120166
94857686321084
101401212412022
114a02839713a5
121a769325061a
13a2197b55a37
144bb6764aa6a
15266ae7ed017
hex1463ec4a076

1401212412022 has 16 divisors (see below), whose sum is σ = 2108026645200. Its totient is φ = 698537217888.

The previous prime is 1401212412011. The next prime is 1401212412071. The reversal of 1401212412022 is 2202142121041.

It is a super-2 number, since 2×14012124120222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1401212411984 and 1401212412002.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8431213 + ... + 8595799.

It is an arithmetic number, because the mean of its divisors is an integer number (131751665325).

Almost surely, 21401212412022 is an apocalyptic number.

1401212412022 is a deficient number, since it is larger than the sum of its proper divisors (706814233178).

1401212412022 is a wasteful number, since it uses less digits than its factorization.

1401212412022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 177135.

The product of its (nonzero) digits is 512, while the sum is 22.

Adding to 1401212412022 its reverse (2202142121041), we get a palindrome (3603354533063).

The spelling of 1401212412022 in words is "one trillion, four hundred one billion, two hundred twelve million, four hundred twelve thousand, twenty-two".

Divisors: 1 2 349 698 12197 24394 164587 329174 4256753 8513506 57440863 114881726 2007467639 4014935278 700606206011 1401212412022