Base | Representation |
---|---|
bin | 11111110111000010010000… |
… | …101101111101000001011011 |
3 | 200101010110221010222001221211 |
4 | 133313002100231331001123 |
5 | 121331222202400431420 |
6 | 1214002522405443551 |
7 | 41341303635022600 |
oct | 3767022055750133 |
9 | 611113833861854 |
10 | 140121441030235 |
11 | 40713195559745 |
12 | 138705831105b7 |
13 | 602551a310c82 |
14 | 2685cb1b866a7 |
15 | 112ed30c3de5a |
hex | 7f7090b7d05b |
140121441030235 has 24 divisors (see below), whose sum is σ = 198074018450880. Its totient is φ = 94867029863424.
The previous prime is 140121441030217. The next prime is 140121441030283. The reversal of 140121441030235 is 532030144121041.
It is a happy number.
It is not a de Polignac number, because 140121441030235 - 233 = 140112851095643 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140121441030197 and 140121441030206.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3619754374 + ... + 3619793083.
It is an arithmetic number, because the mean of its divisors is an integer number (8253084102120).
Almost surely, 2140121441030235 is an apocalyptic number.
140121441030235 is a deficient number, since it is larger than the sum of its proper divisors (57952577420645).
140121441030235 is an equidigital number, since it uses as much as digits as its factorization.
140121441030235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7239547555 (or 7239547548 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 140121441030235 its reverse (532030144121041), we get a palindrome (672151585151276).
The spelling of 140121441030235 in words is "one hundred forty trillion, one hundred twenty-one billion, four hundred forty-one million, thirty thousand, two hundred thirty-five".
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