Base | Representation |
---|---|
bin | 1100101111100111010101… |
… | …1010100110000000011101 |
3 | 1211121112211001100202122001 |
4 | 3023321311122212000131 |
5 | 3314033342211201440 |
6 | 45445032212522301 |
7 | 2644226135146120 |
oct | 313716532460035 |
9 | 54545731322561 |
10 | 14012153225245 |
11 | 451258022169a |
12 | 16a3795920391 |
13 | 7a8456a766a6 |
14 | 3662985743b7 |
15 | 19474cd38b9a |
hex | cbe756a601d |
14012153225245 has 32 divisors (see below), whose sum is σ = 19241563944960. Its totient is φ = 9595887720000.
The previous prime is 14012153225237. The next prime is 14012153225263. The reversal of 14012153225245 is 54252235121041.
It is not a de Polignac number, because 14012153225245 - 23 = 14012153225237 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 386513370 + ... + 386549620.
It is an arithmetic number, because the mean of its divisors is an integer number (601298873280).
Almost surely, 214012153225245 is an apocalyptic number.
It is an amenable number.
14012153225245 is a deficient number, since it is larger than the sum of its proper divisors (5229410719715).
14012153225245 is a wasteful number, since it uses less digits than its factorization.
14012153225245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50265.
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 14012153225245 its reverse (54252235121041), we get a palindrome (68264388346286).
The spelling of 14012153225245 in words is "fourteen trillion, twelve billion, one hundred fifty-three million, two hundred twenty-five thousand, two hundred forty-five".
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