Base | Representation |
---|---|
bin | 11111110111000010110010… |
… | …101000100011100010000111 |
3 | 200101010112101210122210020102 |
4 | 133313002302220203202013 |
5 | 121331224334032243310 |
6 | 1214003055053354315 |
7 | 41341324014361532 |
oct | 3767026250434207 |
9 | 611115353583212 |
10 | 140122010040455 |
11 | 40713457770523 |
12 | 1387070179899b |
13 | 60255ab179201 |
14 | 2685d27583a19 |
15 | 112ed65b898a5 |
hex | 7f70b2a23887 |
140122010040455 has 16 divisors (see below), whose sum is σ = 169077342631104. Its totient is φ = 111478541141760.
The previous prime is 140122010040443. The next prime is 140122010040487. The reversal of 140122010040455 is 554040010221041.
It is a happy number.
It is not a de Polignac number, because 140122010040455 - 214 = 140122010024071 is a prime.
It is a super-3 number, since 3×1401220100404553 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 96371627 + ... + 97814796.
It is an arithmetic number, because the mean of its divisors is an integer number (10567333914444).
Almost surely, 2140122010040455 is an apocalyptic number.
140122010040455 is a deficient number, since it is larger than the sum of its proper divisors (28955332590649).
140122010040455 is a wasteful number, since it uses less digits than its factorization.
140122010040455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 194187226.
The product of its (nonzero) digits is 6400, while the sum is 29.
Adding to 140122010040455 its reverse (554040010221041), we get a palindrome (694162020261496).
The spelling of 140122010040455 in words is "one hundred forty trillion, one hundred twenty-two billion, ten million, forty thousand, four hundred fifty-five".
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