14012233000401 has 4 divisors (see below), whose sum is σ = 18682977333872. Its totient is φ = 9341488666932.

The previous prime is 14012233000379. The next prime is 14012233000453. The reversal of 14012233000401 is 10400033221041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14012233000401 - 2⁵ = 14012233000369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14012233000501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335372166731 + ... + 2335372166736.

It is an arithmetic number, because the mean of its divisors is an integer number (4670744333468).

Almost surely, 2^{14012233000401} is an apocalyptic number.

It is an amenable number.

14012233000401 is a deficient number, since it is larger than the sum of its proper divisors (4670744333471).

14012233000401 is an equidigital number, since it uses as much as digits as its factorization.

14012233000401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4670744333470.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14012233000401 its reverse (10400033221041), we get a palindrome (24412266221442).

The spelling of 14012233000401 in words is "fourteen trillion, twelve billion, two hundred thirty-three million, four hundred one", and thus it is an aban number.