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14012233000453 is a prime number
BaseRepresentation
bin1100101111100111101000…
…1010111010011000000101
31211121120000121110202122101
43023321322022322120011
53314034023122003303
645445044142432101
72644231124214652
oct313717212723005
954546017422571
1014012233000453
114512611259a16
1216a37b8592631
137a846a45865c
143662a4dbcc29
15194754d45d1d
hexcbe7a2ba605

14012233000453 has 2 divisors, whose sum is σ = 14012233000454. Its totient is φ = 14012233000452.

The previous prime is 14012233000379. The next prime is 14012233000489. The reversal of 14012233000453 is 35400033221041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13638670005249 + 373562995204 = 3693057^2 + 611198^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14012233000453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14012233003453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006116500226 + 7006116500227.

It is an arithmetic number, because the mean of its divisors is an integer number (7006116500227).

Almost surely, 214012233000453 is an apocalyptic number.

It is an amenable number.

14012233000453 is a deficient number, since it is larger than the sum of its proper divisors (1).

14012233000453 is an equidigital number, since it uses as much as digits as its factorization.

14012233000453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 14012233000453 its reverse (35400033221041), we get a palindrome (49412266221494).

The spelling of 14012233000453 in words is "fourteen trillion, twelve billion, two hundred thirty-three million, four hundred fifty-three", and thus it is an aban number.