Base | Representation |
---|---|
bin | 1100101111100111101000… |
… | …1010111010011000110101 |
3 | 1211121120000121110202201011 |
4 | 3023321322022322120311 |
5 | 3314034023122004001 |
6 | 45445044142432221 |
7 | 2644231124215051 |
oct | 313717212723065 |
9 | 54546017422634 |
10 | 14012233000501 |
11 | 4512611259a5a |
12 | 16a37b8592671 |
13 | 7a846a458698 |
14 | 3662a4dbcc61 |
15 | 194754d45d51 |
hex | cbe7a2ba635 |
14012233000501 has 2 divisors, whose sum is σ = 14012233000502. Its totient is φ = 14012233000500.
The previous prime is 14012233000489. The next prime is 14012233000529. The reversal of 14012233000501 is 10500033221041.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13562831700625 + 449401299876 = 3682775^2 + 670374^2 .
It is a cyclic number.
It is not a de Polignac number, because 14012233000501 - 213 = 14012232992309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14012233004501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006116500250 + 7006116500251.
It is an arithmetic number, because the mean of its divisors is an integer number (7006116500251).
Almost surely, 214012233000501 is an apocalyptic number.
It is an amenable number.
14012233000501 is a deficient number, since it is larger than the sum of its proper divisors (1).
14012233000501 is an equidigital number, since it uses as much as digits as its factorization.
14012233000501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 14012233000501 its reverse (10500033221041), we get a palindrome (24512266221542).
The spelling of 14012233000501 in words is "fourteen trillion, twelve billion, two hundred thirty-three million, five hundred one", and thus it is an aban number.
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