140123010352500 has 540 divisors, whose sum is σ = 521923980742164. Its totient is φ = 31589357184000.

The previous prime is 140123010352487. The next prime is 140123010352517. The reversal of 140123010352500 is 5253010321041.

140123010352500 is a `hidden beast` number, since 1 + 4 + 0 + 1 + 2 + 3 + 0 + 103 + 52 + 500 = 666.

140123010352500 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 10 ways, for example, as 67722958524816 + 72400051827684 = 8229396^2 + 8508822^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 179 ways as a sum of consecutive naturals, for example, 79611982 + ... + 81353018.

Almost surely, 2^{140123010352500} is an apocalyptic number.

140123010352500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 140123010352500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (260961990371082).

140123010352500 is an abundant number, since it is smaller than the sum of its proper divisors (381800970389664).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140123010352500 is a wasteful number, since it uses less digits than its factorization.

140123010352500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1741154 (or 1741127 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 27.

Adding to 140123010352500 its reverse (5253010321041), we get a palindrome (145376020673541).

The spelling of 140123010352500 in words is "one hundred forty trillion, one hundred twenty-three billion, ten million, three hundred fifty-two thousand, five hundred".