Base | Representation |
---|---|
bin | 11111110111000011110000… |
… | …110001011011101101111011 |
3 | 200101010122002110100000112002 |
4 | 133313003300301123231323 |
5 | 121331234002423231011 |
6 | 1214003350334211215 |
7 | 41341361603533112 |
oct | 3767036061335573 |
9 | 611118073300462 |
10 | 140123052555131 |
11 | 407139421921a8 |
12 | 13870952953b0b |
13 | 60257161506b9 |
14 | 2685dc5bdac79 |
15 | 112edc7467c3b |
hex | 7f70f0c5bb7b |
140123052555131 has 64 divisors (see below), whose sum is σ = 155152287392256. Its totient is φ = 126014251776000.
The previous prime is 140123052555121. The next prime is 140123052555173. The reversal of 140123052555131 is 131555250321041.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140123052555131 is a prime.
It is a super-2 number, since 2×1401230525551312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140123052555121) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 20910764081 + ... + 20910770781.
It is an arithmetic number, because the mean of its divisors is an integer number (2424254490504).
Almost surely, 2140123052555131 is an apocalyptic number.
140123052555131 is a deficient number, since it is larger than the sum of its proper divisors (15029234837125).
140123052555131 is a wasteful number, since it uses less digits than its factorization.
140123052555131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10172.
The product of its (nonzero) digits is 90000, while the sum is 38.
The spelling of 140123052555131 in words is "one hundred forty trillion, one hundred twenty-three billion, fifty-two million, five hundred fifty-five thousand, one hundred thirty-one".
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