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14012306205649 is a prime number
BaseRepresentation
bin1100101111100111111010…
…0010001010101111010001
31211121120012201012222021221
43023321332202022233101
53314034200342040044
645445055315445041
72644233003361123
oct313717642125721
954546181188257
1014012306205649
11451264960a084
1216a3818bb6781
137a847c67a03b
143662b09d7213
1519475b4a6484
hexcbe7e88abd1

14012306205649 has 2 divisors, whose sum is σ = 14012306205650. Its totient is φ = 14012306205648.

The previous prime is 14012306205607. The next prime is 14012306205659. The reversal of 14012306205649 is 94650260321041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11367470778624 + 2644835427025 = 3371568^2 + 1626295^2 .

It is a cyclic number.

It is not a de Polignac number, because 14012306205649 - 217 = 14012306074577 is a prime.

It is a super-2 number, since 2×140123062056492 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14012306205659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006153102824 + 7006153102825.

It is an arithmetic number, because the mean of its divisors is an integer number (7006153102825).

Almost surely, 214012306205649 is an apocalyptic number.

It is an amenable number.

14012306205649 is a deficient number, since it is larger than the sum of its proper divisors (1).

14012306205649 is an equidigital number, since it uses as much as digits as its factorization.

14012306205649 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 14012306205649 in words is "fourteen trillion, twelve billion, three hundred six million, two hundred five thousand, six hundred forty-nine".