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14012335401 = 34670778467
BaseRepresentation
bin11010000110011001…
…10100010100101001
31100011112200101120020
431003030310110221
5212144124213101
610234232551053
71004144612541
oct150314642451
940145611506
1014012335401
115a40663a89
122870852489
13142403a72c
1496cda8321
1557026d136
hex343334529

14012335401 has 4 divisors (see below), whose sum is σ = 18683113872. Its totient is φ = 9341556932.

The previous prime is 14012335361. The next prime is 14012335433. The reversal of 14012335401 is 10453321041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14012335401 - 214 = 14012319017 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14012335301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335389231 + ... + 2335389236.

It is an arithmetic number, because the mean of its divisors is an integer number (4670778468).

Almost surely, 214012335401 is an apocalyptic number.

It is an amenable number.

14012335401 is a deficient number, since it is larger than the sum of its proper divisors (4670778471).

14012335401 is an equidigital number, since it uses as much as digits as its factorization.

14012335401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4670778470.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 14012335401 its reverse (10453321041), we get a palindrome (24465656442).

The spelling of 14012335401 in words is "fourteen billion, twelve million, three hundred thirty-five thousand, four hundred one".

Divisors: 1 3 4670778467 14012335401