Search a number
-
+
1401243134321 is a prime number
BaseRepresentation
bin10100011001000000100…
…110010110100101110001
311221221212001011120011202
4110121000212112211301
5140424221220244241
62551415555220545
7203144053056242
oct24310046264561
94857761146152
101401243134321
114a029a245528
121a76a15a7755
13a21a1321704
144bb6b766cc9
15266b236ad9b
hex14640996971

1401243134321 has 2 divisors, whose sum is σ = 1401243134322. Its totient is φ = 1401243134320.

The previous prime is 1401243134273. The next prime is 1401243134363. The reversal of 1401243134321 is 1234313421041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1372787155600 + 28455978721 = 1171660^2 + 168689^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1401243134321 is a prime.

It is not a weakly prime, because it can be changed into another prime (1401243137321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700621567160 + 700621567161.

It is an arithmetic number, because the mean of its divisors is an integer number (700621567161).

Almost surely, 21401243134321 is an apocalyptic number.

It is an amenable number.

1401243134321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401243134321 is an equidigital number, since it uses as much as digits as its factorization.

1401243134321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1401243134321 its reverse (1234313421041), we get a palindrome (2635556555362).

The spelling of 1401243134321 in words is "one trillion, four hundred one billion, two hundred forty-three million, one hundred thirty-four thousand, three hundred twenty-one".