14012502650137 has 2 divisors, whose sum is σ = 14012502650138. Its totient is φ = 14012502650136.

The previous prime is 14012502650129. The next prime is 14012502650147. The reversal of 14012502650137 is 73105620521041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9202358864521 + 4810143785616 = 3033539^2 + 2193204^2 .

It is a cyclic number.

It is not a de Polignac number, because 14012502650137 - 2³ = 14012502650129 is a prime.

It is a super-2 number, since 2×14012502650137² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14012502650096 and 14012502650105.

It is not a weakly prime, because it can be changed into another prime (14012502650147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006251325068 + 7006251325069.

It is an arithmetic number, because the mean of its divisors is an integer number (7006251325069).

Almost surely, 2^{14012502650137} is an apocalyptic number.

It is an amenable number.

14012502650137 is a deficient number, since it is larger than the sum of its proper divisors (1).

14012502650137 is an equidigital number, since it uses as much as digits as its factorization.

14012502650137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 37.

The spelling of 14012502650137 in words is "fourteen trillion, twelve billion, five hundred two million, six hundred fifty thousand, one hundred thirty-seven".