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14013120203400 = 23352231496815057
BaseRepresentation
bin1100101111101010111100…
…0011010100101010001000
31211121122022102220100021210
43023322233003110222020
53314042332233002100
645445312154333120
72644262116264323
oct313725703245210
954548272810253
1014013120203400
114512a2704069a
1216a3a0572a1a0
137a857c1c1306
1436634ab677ba
151947a7b95c50
hexcbeaf0d4a88

14013120203400 has 192 divisors, whose sum is σ = 45633628368000. Its totient is φ = 3550371573760.

The previous prime is 14013120203347. The next prime is 14013120203431. The reversal of 14013120203400 is 430202131041.

14013120203400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1351329 + ... + 5463728.

It is an arithmetic number, because the mean of its divisors is an integer number (237675147750).

Almost surely, 214013120203400 is an apocalyptic number.

14013120203400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14013120203400 is an abundant number, since it is smaller than the sum of its proper divisors (31620508164600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14013120203400 is a wasteful number, since it uses less digits than its factorization.

14013120203400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6815248 (or 6815239 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14013120203400 its reverse (430202131041), we get a palindrome (14443322334441).

The spelling of 14013120203400 in words is "fourteen trillion, thirteen billion, one hundred twenty million, two hundred three thousand, four hundred".