14013133304140 has 12 divisors (see below), whose sum is σ = 29427579938736. Its totient is φ = 5605253321648.

The previous prime is 14013133304099. The next prime is 14013133304189. The reversal of 14013133304140 is 4140333131041.

It is a super-3 number, since 3×14013133304140³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14013133304099 and 14013133304108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 350328332584 + ... + 350328332623.

It is an arithmetic number, because the mean of its divisors is an integer number (2452298328228).

Almost surely, 2^{14013133304140} is an apocalyptic number.

14013133304140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14013133304140 is an abundant number, since it is smaller than the sum of its proper divisors (15414446634596).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14013133304140 is a wasteful number, since it uses less digits than its factorization.

14013133304140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 700656665216 (or 700656665214 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 14013133304140 its reverse (4140333131041), we get a palindrome (18153466435181).

The spelling of 14013133304140 in words is "fourteen trillion, thirteen billion, one hundred thirty-three million, three hundred four thousand, one hundred forty".