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140135124103 = 1313617920371
BaseRepresentation
bin1000001010000010110…
…1000100110010000111
3111101201020221220011121
42002200231010302013
54243444042432403
6144213250014411
713060451621062
oct2024055046207
9441636856147
10140135124103
1154481695957
12231aab77407
13102a3882ba0
146ad55638d9
1539a2a133bd
hex20a0b44c87

140135124103 has 8 divisors (see below), whose sum is σ = 151025653296. Its totient is φ = 129260438400.

The previous prime is 140135124091. The next prime is 140135124121. The reversal of 140135124103 is 301421531041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140135124103 - 25 = 140135124071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140135124163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3942493 + ... + 3977878.

It is an arithmetic number, because the mean of its divisors is an integer number (18878206662).

Almost surely, 2140135124103 is an apocalyptic number.

140135124103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

140135124103 is a deficient number, since it is larger than the sum of its proper divisors (10890529193).

140135124103 is a wasteful number, since it uses less digits than its factorization.

140135124103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7921745.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 140135124103 its reverse (301421531041), we get a palindrome (441556655144).

The spelling of 140135124103 in words is "one hundred forty billion, one hundred thirty-five million, one hundred twenty-four thousand, one hundred three".

Divisors: 1 13 1361 17693 7920371 102964823 10779624931 140135124103