140140003111 has 4 divisors (see below), whose sum is σ = 140140889424. Its totient is φ = 140139116800.

The previous prime is 140140003109. The next prime is 140140003121. The reversal of 140140003111 is 111300041041.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 140140003111 - 2¹ = 140140003109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140140003121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134170 + ... + 546151.

It is an arithmetic number, because the mean of its divisors is an integer number (35035222356).

Almost surely, 2^140140003111 is an apocalyptic number.

140140003111 is a deficient number, since it is larger than the sum of its proper divisors (886313).

140140003111 is an equidigital number, since it uses as much as digits as its factorization.

140140003111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 886312.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 140140003111 its reverse (111300041041), we get a palindrome (251440044152).

The spelling of 140140003111 in words is "one hundred forty billion, one hundred forty million, three thousand, one hundred eleven".