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14014112143111 = 33142338707381
BaseRepresentation
bin1100101111101110101000…
…1011010001011100000111
31211121201212120102002202121
43023323222023101130013
53314101400202034421
645445554431150411
72644325522524663
oct313735213213407
954551776362677
1014014112143111
114513395a59683
1216a4041975407
137a86a98687a2
143664027b78a3
15194814cd3d41
hexcbeea2d1707

14014112143111 has 4 divisors (see below), whose sum is σ = 14056450850824. Its totient is φ = 13971773435400.

The previous prime is 14014112143063. The next prime is 14014112143139. The reversal of 14014112143111 is 11134121141041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14014112143111 - 29 = 14014112142599 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14014112143411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21169353360 + ... + 21169354021.

It is an arithmetic number, because the mean of its divisors is an integer number (3514112712706).

Almost surely, 214014112143111 is an apocalyptic number.

14014112143111 is a deficient number, since it is larger than the sum of its proper divisors (42338707713).

14014112143111 is an equidigital number, since it uses as much as digits as its factorization.

14014112143111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42338707712.

The product of its (nonzero) digits is 384, while the sum is 25.

Adding to 14014112143111 its reverse (11134121141041), we get a palindrome (25148233284152).

The spelling of 14014112143111 in words is "fourteen trillion, fourteen billion, one hundred twelve million, one hundred forty-three thousand, one hundred eleven".

Divisors: 1 331 42338707381 14014112143111