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14014213123 is a prime number
BaseRepresentation
bin11010000110100111…
…11110110000000011
31100011200012210022111
431003103332300003
5212200114304443
610234341120151
71004166563131
oct150323766003
940150183274
1014014213123
115a41726819
1228713b9057
131424547301
1496d336751
155704de69d
hex3434fec03

14014213123 has 2 divisors, whose sum is σ = 14014213124. Its totient is φ = 14014213122.

The previous prime is 14014213111. The next prime is 14014213133. The reversal of 14014213123 is 32131241041.

14014213123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14014213123 - 25 = 14014213091 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14014213094 and 14014213103.

It is not a weakly prime, because it can be changed into another prime (14014213133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7007106561 + 7007106562.

It is an arithmetic number, because the mean of its divisors is an integer number (7007106562).

Almost surely, 214014213123 is an apocalyptic number.

14014213123 is a deficient number, since it is larger than the sum of its proper divisors (1).

14014213123 is an equidigital number, since it uses as much as digits as its factorization.

14014213123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 14014213123 its reverse (32131241041), we get a palindrome (46145454164).

The spelling of 14014213123 in words is "fourteen billion, fourteen million, two hundred thirteen thousand, one hundred twenty-three".