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140142240315433 is a prime number
BaseRepresentation
bin11111110111010101101000…
…011100111011100000101001
3200101012110121200111020101001
4133313111220130323200221
5121332042302010043213
61214020242330355001
741342641234025206
oct3767255034734051
9611173550436331
10140142240315433
1140720a99180544
121387460888ba61
13602748347b315
142686cc628ccad
15113064bc401dd
hex7f756873b829

140142240315433 has 2 divisors, whose sum is σ = 140142240315434. Its totient is φ = 140142240315432.

The previous prime is 140142240315397. The next prime is 140142240315449. The reversal of 140142240315433 is 334513042241041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106981538003344 + 33160702312089 = 10343188^2 + 5758533^2 .

It is a cyclic number.

It is not a de Polignac number, because 140142240315433 - 217 = 140142240184361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140142240315392 and 140142240315401.

It is not a weakly prime, because it can be changed into another prime (140142240315733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70071120157716 + 70071120157717.

It is an arithmetic number, because the mean of its divisors is an integer number (70071120157717).

Almost surely, 2140142240315433 is an apocalyptic number.

It is an amenable number.

140142240315433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140142240315433 is an equidigital number, since it uses as much as digits as its factorization.

140142240315433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 140142240315433 its reverse (334513042241041), we get a palindrome (474655282556474).

The spelling of 140142240315433 in words is "one hundred forty trillion, one hundred forty-two billion, two hundred forty million, three hundred fifteen thousand, four hundred thirty-three".