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14014233244331 is a prime number
BaseRepresentation
bin1100101111101111000101…
…1001001111001010101011
31211121202012000021200101222
43023323301121033022223
53314102122202304311
645450014434532255
72644331523053525
oct313736131171253
954552160250358
1014014233244331
114513448352831
1216a407643708b
137a86c8989a08
143664148dca15
15194820755adb
hexcbef164f2ab

14014233244331 has 2 divisors, whose sum is σ = 14014233244332. Its totient is φ = 14014233244330.

The previous prime is 14014233244313. The next prime is 14014233244373. The reversal of 14014233244331 is 13344233241041.

Together with previous prime (14014233244313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14014233244331 is a prime.

It is a super-2 number, since 2×140142332443312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14014233244291 and 14014233244300.

It is not a weakly prime, because it can be changed into another prime (14014233241331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7007116622165 + 7007116622166.

It is an arithmetic number, because the mean of its divisors is an integer number (7007116622166).

Almost surely, 214014233244331 is an apocalyptic number.

14014233244331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14014233244331 is an equidigital number, since it uses as much as digits as its factorization.

14014233244331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 14014233244331 its reverse (13344233241041), we get a palindrome (27358466485372).

The spelling of 14014233244331 in words is "fourteen trillion, fourteen billion, two hundred thirty-three million, two hundred forty-four thousand, three hundred thirty-one".