Base | Representation |
---|---|
bin | 101001110001101… |
… | …0100100100101001 |
3 | 10121200200012111222 |
4 | 1103203110210221 |
5 | 10332323040413 |
6 | 351032431425 |
7 | 46510555565 |
oct | 12343244451 |
9 | 3550605458 |
10 | 1401768233 |
11 | 65a297248 |
12 | 331548575 |
13 | 19454a578 |
14 | d42526a5 |
15 | 830e3b08 |
hex | 538d4929 |
1401768233 has 2 divisors, whose sum is σ = 1401768234. Its totient is φ = 1401768232.
The previous prime is 1401768217. The next prime is 1401768241. The reversal of 1401768233 is 3328671041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1116428569 + 285339664 = 33413^2 + 16892^2 .
It is an emirp because it is prime and its reverse (3328671041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1401768233 - 24 = 1401768217 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1401768193 and 1401768202.
It is not a weakly prime, because it can be changed into another prime (1401768253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700884116 + 700884117.
It is an arithmetic number, because the mean of its divisors is an integer number (700884117).
Almost surely, 21401768233 is an apocalyptic number.
It is an amenable number.
1401768233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401768233 is an equidigital number, since it uses as much as digits as its factorization.
1401768233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 35.
The square root of 1401768233 is about 37440.1954188276. The cubic root of 1401768233 is about 1119.1597207698.
The spelling of 1401768233 in words is "one billion, four hundred one million, seven hundred sixty-eight thousand, two hundred thirty-three".
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