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14020013142307 is a prime number
BaseRepresentation
bin1100110000000100100111…
…1001110011000100100011
31211122022002211011220212101
43030001021321303010203
53314200441331023212
645452412150111231
72644624665302164
oct314011171630443
954568084156771
1014020013142307
114515943a10717
1216a520a04b517
137a910a2807a3
143668023b576b
15194a5cdb3157
hexcc049e73123

14020013142307 has 2 divisors, whose sum is σ = 14020013142308. Its totient is φ = 14020013142306.

The previous prime is 14020013142287. The next prime is 14020013142313. The reversal of 14020013142307 is 70324131002041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14020013142307 - 215 = 14020013109539 is a prime.

It is a super-3 number, since 3×140200131423073 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14020013143307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7010006571153 + 7010006571154.

It is an arithmetic number, because the mean of its divisors is an integer number (7010006571154).

Almost surely, 214020013142307 is an apocalyptic number.

14020013142307 is a deficient number, since it is larger than the sum of its proper divisors (1).

14020013142307 is an equidigital number, since it uses as much as digits as its factorization.

14020013142307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 14020013142307 its reverse (70324131002041), we get a palindrome (84344144144348).

The spelling of 14020013142307 in words is "fourteen trillion, twenty billion, thirteen million, one hundred forty-two thousand, three hundred seven".