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140210005211 is a prime number
BaseRepresentation
bin1000001010010100101…
…0101110010011011011
3111101220110212020201222
42002211022232103123
54244122230131321
6144224523002255
713062351244253
oct2024512562333
9441813766658
10140210005211
115450a990171
122321006938b
13102b6240333
146b01496963
1539a93a53ab
hex20a52ae4db

140210005211 has 2 divisors, whose sum is σ = 140210005212. Its totient is φ = 140210005210.

The previous prime is 140210005157. The next prime is 140210005279. The reversal of 140210005211 is 112500012041.

It is a weak prime.

It is an emirp because it is prime and its reverse (112500012041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140210005211 - 218 = 140209743067 is a prime.

It is a super-2 number, since 2×1402100052112 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 140210005211.

It is not a weakly prime, because it can be changed into another prime (140210025211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70105002605 + 70105002606.

It is an arithmetic number, because the mean of its divisors is an integer number (70105002606).

Almost surely, 2140210005211 is an apocalyptic number.

140210005211 is a deficient number, since it is larger than the sum of its proper divisors (1).

140210005211 is an equidigital number, since it uses as much as digits as its factorization.

140210005211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 17.

Adding to 140210005211 its reverse (112500012041), we get a palindrome (252710017252).

The spelling of 140210005211 in words is "one hundred forty billion, two hundred ten million, five thousand, two hundred eleven".