Base | Representation |
---|---|
bin | 1000001010010101001… |
… | …1001011000011011011 |
3 | 111101220122000210000202 |
4 | 2002211103023003123 |
5 | 4244123312020443 |
6 | 144225042252415 |
7 | 13062406130603 |
oct | 2024523130333 |
9 | 441818023022 |
10 | 140212220123 |
11 | 54511163278 |
12 | 2321095710b |
13 | 102b6837531 |
14 | 6b018b1c03 |
15 | 39a96917b8 |
hex | 20a54cb0db |
140212220123 has 2 divisors, whose sum is σ = 140212220124. Its totient is φ = 140212220122.
The previous prime is 140212220119. The next prime is 140212220219. The reversal of 140212220123 is 321022212041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140212220123 - 22 = 140212220119 is a prime.
It is a super-2 number, since 2×1402122201232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 140212220095 and 140212220104.
It is not a weakly prime, because it can be changed into another prime (140212220023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106110061 + 70106110062.
It is an arithmetic number, because the mean of its divisors is an integer number (70106110062).
Almost surely, 2140212220123 is an apocalyptic number.
140212220123 is a deficient number, since it is larger than the sum of its proper divisors (1).
140212220123 is an equidigital number, since it uses as much as digits as its factorization.
140212220123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 140212220123 its reverse (321022212041), we get a palindrome (461234432164).
The spelling of 140212220123 in words is "one hundred forty billion, two hundred twelve million, two hundred twenty thousand, one hundred twenty-three".
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