Base | Representation |
---|---|
bin | 11010000111011101… |
… | …01110010000010011 |
3 | 1100012011101221122222 |
4 | 31003232232100103 |
5 | 212203413122233 |
6 | 10235151251255 |
7 | 1004313301313 |
oct | 150356562023 |
9 | 40164357588 |
10 | 14021223443 |
11 | 5a45684777 |
12 | 2873819b2b |
13 | 1425b30126 |
14 | 97023d443 |
15 | 570e26898 |
hex | 343bae413 |
14021223443 has 2 divisors, whose sum is σ = 14021223444. Its totient is φ = 14021223442.
The previous prime is 14021223367. The next prime is 14021223457. The reversal of 14021223443 is 34432212041.
14021223443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14021223443 - 216 = 14021157907 is a prime.
It is not a weakly prime, because it can be changed into another prime (14021223043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7010611721 + 7010611722.
It is an arithmetic number, because the mean of its divisors is an integer number (7010611722).
Almost surely, 214021223443 is an apocalyptic number.
14021223443 is a deficient number, since it is larger than the sum of its proper divisors (1).
14021223443 is an equidigital number, since it uses as much as digits as its factorization.
14021223443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 14021223443 its reverse (34432212041), we get a palindrome (48453435484).
The spelling of 14021223443 in words is "fourteen billion, twenty-one million, two hundred twenty-three thousand, four hundred forty-three".
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