Base | Representation |
---|---|
bin | 11111111000010111101000… |
… | …000001001110010111001001 |
3 | 200101110020112000111211121022 |
4 | 133320113220001032113021 |
5 | 121334222412100404001 |
6 | 1214113001531522225 |
7 | 41351030220355601 |
oct | 3770275001162711 |
9 | 611406460454538 |
10 | 140213100013001 |
11 | 40749050678074 |
12 | 138862a35b9375 |
13 | 6031066a4ac52 |
14 | 268a4c912dc01 |
15 | 11323e7a6b11b |
hex | 7f85e804e5c9 |
140213100013001 has 2 divisors, whose sum is σ = 140213100013002. Its totient is φ = 140213100013000.
The previous prime is 140213100012983. The next prime is 140213100013141. The reversal of 140213100013001 is 100310001312041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 110293075206601 + 29920024806400 = 10502051^2 + 5469920^2 .
It is a cyclic number.
It is not a de Polignac number, because 140213100013001 - 214 = 140213099996617 is a prime.
It is not a weakly prime, because it can be changed into another prime (140213100013601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70106550006500 + 70106550006501.
It is an arithmetic number, because the mean of its divisors is an integer number (70106550006501).
Almost surely, 2140213100013001 is an apocalyptic number.
It is an amenable number.
140213100013001 is a deficient number, since it is larger than the sum of its proper divisors (1).
140213100013001 is an equidigital number, since it uses as much as digits as its factorization.
140213100013001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 140213100013001 its reverse (100310001312041), we get a palindrome (240523101325042).
The spelling of 140213100013001 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred million, thirteen thousand, one".
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