Base | Representation |
---|---|
bin | 11111111000010111101000… |
… | …101111000010110100010111 |
3 | 200101110020112212010002001211 |
4 | 133320113220233002310113 |
5 | 121334222423134234333 |
6 | 1214113003041202251 |
7 | 41351030424433231 |
oct | 3770275057026427 |
9 | 611406485102054 |
10 | 140213112024343 |
11 | 407490574313a6 |
12 | 138862a7630387 |
13 | 6031069395157 |
14 | 268a4ca979251 |
15 | 11323e8b3eecd |
hex | 7f85e8bc2d17 |
140213112024343 has 4 divisors (see below), whose sum is σ = 148460942143440. Its totient is φ = 131965281905248.
The previous prime is 140213112024331. The next prime is 140213112024439. The reversal of 140213112024343 is 343420211312041.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140213112024343 - 225 = 140213078469911 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140213112024043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4123915059523 + ... + 4123915059556.
It is an arithmetic number, because the mean of its divisors is an integer number (37115235535860).
Almost surely, 2140213112024343 is an apocalyptic number.
140213112024343 is a deficient number, since it is larger than the sum of its proper divisors (8247830119097).
140213112024343 is an equidigital number, since it uses as much as digits as its factorization.
140213112024343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8247830119096.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 140213112024343 its reverse (343420211312041), we get a palindrome (483633323336384).
The spelling of 140213112024343 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred twelve million, twenty-four thousand, three hundred forty-three".
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