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1402133113 is a prime number
BaseRepresentation
bin101001110010010…
…1101101001111001
310121201100202001001
41103210231221321
510332421224423
6351044325001
746513635433
oct12344555171
93551322031
101402133113
1165a5163a7
123316a3761
13194647684
14d4309653
1583166cad
hex5392da79

1402133113 has 2 divisors, whose sum is σ = 1402133114. Its totient is φ = 1402133112.

The previous prime is 1402133099. The next prime is 1402133137. The reversal of 1402133113 is 3113312041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 904084624 + 498048489 = 30068^2 + 22317^2 .

It is a cyclic number.

It is not a de Polignac number, because 1402133113 - 25 = 1402133081 is a prime.

It is not a weakly prime, because it can be changed into another prime (1402133143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701066556 + 701066557.

It is an arithmetic number, because the mean of its divisors is an integer number (701066557).

Almost surely, 21402133113 is an apocalyptic number.

It is an amenable number.

1402133113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1402133113 is an equidigital number, since it uses as much as digits as its factorization.

1402133113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1402133113 is about 37445.0679395832. The cubic root of 1402133113 is about 1119.2568180318.

Adding to 1402133113 its reverse (3113312041), we get a palindrome (4515445154).

The spelling of 1402133113 in words is "one billion, four hundred two million, one hundred thirty-three thousand, one hundred thirteen".