Base | Representation |
---|---|
bin | 10100011001110101101… |
… | …010000111000111111001 |
3 | 11222001011002012021101011 |
4 | 110121311222013013321 |
5 | 140433032111440433 |
6 | 2552044154553521 |
7 | 203205112335361 |
oct | 24316552070771 |
9 | 4861132167334 |
10 | 1402133311993 |
11 | 4a0706779157 |
12 | 1a78ab7388a1 |
13 | a22b388936b |
14 | 4bc13a879a1 |
15 | 267155a73cd |
hex | 14675a871f9 |
1402133311993 has 2 divisors, whose sum is σ = 1402133311994. Its totient is φ = 1402133311992.
The previous prime is 1402133311949. The next prime is 1402133312011. The reversal of 1402133311993 is 3991133312041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 831939179449 + 570194132544 = 912107^2 + 755112^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1402133311993 is a prime.
It is not a weakly prime, because it can be changed into another prime (1402133311393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701066655996 + 701066655997.
It is an arithmetic number, because the mean of its divisors is an integer number (701066655997).
Almost surely, 21402133311993 is an apocalyptic number.
It is an amenable number.
1402133311993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402133311993 is an equidigital number, since it uses as much as digits as its factorization.
1402133311993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 40.
The spelling of 1402133311993 in words is "one trillion, four hundred two billion, one hundred thirty-three million, three hundred eleven thousand, nine hundred ninety-three".
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