140213421201103 has 4 divisors (see below), whose sum is σ = 140214520205800. Its totient is φ = 140212322196408.

The previous prime is 140213421201067. The next prime is 140213421201137. The reversal of 140213421201103 is 301102124312041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140213421201103 - 2²¹ = 140213419103951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140213421201143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 549310953 + ... + 549566146.

It is an arithmetic number, because the mean of its divisors is an integer number (35053630051450).

Almost surely, 2^{140213421201103} is an apocalyptic number.

140213421201103 is a deficient number, since it is larger than the sum of its proper divisors (1099004697).

140213421201103 is a wasteful number, since it uses less digits than its factorization.

140213421201103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1099004696.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 140213421201103 its reverse (301102124312041), we get a palindrome (441315545513144).

The spelling of 140213421201103 in words is "one hundred forty trillion, two hundred thirteen billion, four hundred twenty-one million, two hundred one thousand, one hundred three".