140214103000111 has 8 divisors (see below), whose sum is σ = 160625317861664. Its totient is φ = 119898045318240.

The previous prime is 140214103000093. The next prime is 140214103000123. The reversal of 140214103000111 is 111000301412041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 140214103000111 - 2⁵ = 140214103000079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140214103000151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23789291760 + ... + 23789297653.

It is an arithmetic number, because the mean of its divisors is an integer number (20078164732708).

Almost surely, 2^{140214103000111} is an apocalyptic number.

140214103000111 is a deficient number, since it is larger than the sum of its proper divisors (20411214861553).

140214103000111 is an equidigital number, since it uses as much as digits as its factorization.

140214103000111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47578589841.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 140214103000111 its reverse (111000301412041), we get a palindrome (251214404412152).

The spelling of 140214103000111 in words is "one hundred forty trillion, two hundred fourteen billion, one hundred three million, one hundred eleven", and thus it is an aban number.