Base | Representation |
---|---|
bin | 1100110000001100001001… |
… | …0110110000100011110001 |
3 | 1211122111022122210010121210 |
4 | 3030003002112300203301 |
5 | 3314214111201000423 |
6 | 45453344500110333 |
7 | 2645026034304666 |
oct | 314030226604361 |
9 | 54574278703553 |
10 | 14022034000113 |
11 | 4516790704037 |
12 | 16a56929953a9 |
13 | 7a936cb4b839 |
14 | 36695493da6d |
15 | 194b2a4e5b93 |
hex | cc0c25b08f1 |
14022034000113 has 32 divisors (see below), whose sum is σ = 20021189667840. Its totient is φ = 8709781893120.
The previous prime is 14022034000109. The next prime is 14022034000127. The reversal of 14022034000113 is 31100043022041.
It is not a de Polignac number, because 14022034000113 - 22 = 14022034000109 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14022034000113.
It is not an unprimeable number, because it can be changed into a prime (14022034000613) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6412156 + ... + 8316237.
It is an arithmetic number, because the mean of its divisors is an integer number (625662177120).
Almost surely, 214022034000113 is an apocalyptic number.
It is an amenable number.
14022034000113 is a deficient number, since it is larger than the sum of its proper divisors (5999155667727).
14022034000113 is a wasteful number, since it uses less digits than its factorization.
14022034000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14728809.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 14022034000113 its reverse (31100043022041), we get a palindrome (45122077022154).
The spelling of 14022034000113 in words is "fourteen trillion, twenty-two billion, thirty-four million, one hundred thirteen", and thus it is an aban number.
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