Base | Representation |
---|---|
bin | 11111111000100001000010… |
… | …111001000001000001010111 |
3 | 200101111012121220202011011120 |
4 | 133320201002321001001113 |
5 | 121334404120404204310 |
6 | 1214121353324535023 |
7 | 41351535655313421 |
oct | 3770410271010127 |
9 | 611435556664146 |
10 | 140223214522455 |
11 | 40752370a93799 |
12 | 138882469b1473 |
13 | 6031cb938c19c |
14 | 268aba857d811 |
15 | 11327da9e7b70 |
hex | 7f8842e41057 |
140223214522455 has 64 divisors (see below), whose sum is σ = 238402299980160. Its totient is φ = 70244776820736.
The previous prime is 140223214522421. The next prime is 140223214522487. The reversal of 140223214522455 is 554225412322041.
It is not a de Polignac number, because 140223214522455 - 217 = 140223214391383 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 106749139 + ... + 108054731.
It is an arithmetic number, because the mean of its divisors is an integer number (3725035937190).
Almost surely, 2140223214522455 is an apocalyptic number.
140223214522455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
140223214522455 is a deficient number, since it is larger than the sum of its proper divisors (98179085457705).
140223214522455 is a wasteful number, since it uses less digits than its factorization.
140223214522455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1312340.
The product of its (nonzero) digits is 768000, while the sum is 42.
Adding to 140223214522455 its reverse (554225412322041), we get a palindrome (694448626844496).
The spelling of 140223214522455 in words is "one hundred forty trillion, two hundred twenty-three billion, two hundred fourteen million, five hundred twenty-two thousand, four hundred fifty-five".
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