Base | Representation |
---|---|
bin | 10100011001111100000… |
… | …011000100111100110011 |
3 | 11222001102112221000002121 |
4 | 110121330003010330303 |
5 | 140433242033114422 |
6 | 2552102544455111 |
7 | 203210553521206 |
oct | 24317403047463 |
9 | 4861375830077 |
10 | 1402240519987 |
11 | 4a07612430aa |
12 | 1a791b61a497 |
13 | a22ccb54948 |
14 | 4bc23dd393d |
15 | 2671ebd28c7 |
hex | 1467c0c4f33 |
1402240519987 has 2 divisors, whose sum is σ = 1402240519988. Its totient is φ = 1402240519986.
The previous prime is 1402240519963. The next prime is 1402240520099. The reversal of 1402240519987 is 7899150422041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1402240519987 - 219 = 1402239995699 is a prime.
It is not a weakly prime, because it can be changed into another prime (1402240519957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 701120259993 + 701120259994.
It is an arithmetic number, because the mean of its divisors is an integer number (701120259994).
Almost surely, 21402240519987 is an apocalyptic number.
1402240519987 is a deficient number, since it is larger than the sum of its proper divisors (1).
1402240519987 is an equidigital number, since it uses as much as digits as its factorization.
1402240519987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1451520, while the sum is 52.
The spelling of 1402240519987 in words is "one trillion, four hundred two billion, two hundred forty million, five hundred nineteen thousand, nine hundred eighty-seven".
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