Base | Representation |
---|---|
bin | 11010000111100110… |
… | …10101100101100001 |
3 | 1100012020200102000212 |
4 | 31003303111211201 |
5 | 212204220324441 |
6 | 10235233223505 |
7 | 1004326500134 |
oct | 150363254541 |
9 | 40166612025 |
10 | 14022433121 |
11 | 5a46330604 |
12 | 2874101b95 |
13 | 1426164908 |
14 | 97047621b |
15 | 5710b4eeb |
hex | 343cd5961 |
14022433121 has 2 divisors, whose sum is σ = 14022433122. Its totient is φ = 14022433120.
The previous prime is 14022433109. The next prime is 14022433147. The reversal of 14022433121 is 12133422041.
14022433121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9127891600 + 4894541521 = 95540^2 + 69961^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14022433121 is a prime.
It is not a weakly prime, because it can be changed into another prime (14022453121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7011216560 + 7011216561.
It is an arithmetic number, because the mean of its divisors is an integer number (7011216561).
Almost surely, 214022433121 is an apocalyptic number.
It is an amenable number.
14022433121 is a deficient number, since it is larger than the sum of its proper divisors (1).
14022433121 is an equidigital number, since it uses as much as digits as its factorization.
14022433121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 14022433121 its reverse (12133422041), we get a palindrome (26155855162).
The spelling of 14022433121 in words is "fourteen billion, twenty-two million, four hundred thirty-three thousand, one hundred twenty-one".
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