Base | Representation |
---|---|
bin | 11111111000100010010001… |
… | …111101101101111011101011 |
3 | 200101111100001101001001222011 |
4 | 133320202101331231323223 |
5 | 121334414330013430201 |
6 | 1214122133115140351 |
7 | 41351613564436063 |
oct | 3770422175557353 |
9 | 611440041031864 |
10 | 140224541155051 |
11 | 40752991921471 |
12 | 138885571446b7 |
13 | 603216b1904a2 |
14 | 268ac928343a3 |
15 | 11328671e9151 |
hex | 7f8891f6deeb |
140224541155051 has 2 divisors, whose sum is σ = 140224541155052. Its totient is φ = 140224541155050.
The previous prime is 140224541155001. The next prime is 140224541155057. The reversal of 140224541155051 is 150551145422041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140224541155051 - 27 = 140224541154923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140224541154995 and 140224541155013.
It is not a weakly prime, because it can be changed into another prime (140224541155057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70112270577525 + 70112270577526.
It is an arithmetic number, because the mean of its divisors is an integer number (70112270577526).
Almost surely, 2140224541155051 is an apocalyptic number.
140224541155051 is a deficient number, since it is larger than the sum of its proper divisors (1).
140224541155051 is an equidigital number, since it uses as much as digits as its factorization.
140224541155051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160000, while the sum is 40.
Adding to 140224541155051 its reverse (150551145422041), we get a palindrome (290775686577092).
The spelling of 140224541155051 in words is "one hundred forty trillion, two hundred twenty-four billion, five hundred forty-one million, one hundred fifty-five thousand, fifty-one".
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