Base | Representation |
---|---|
bin | 1100110000001111110101… |
… | …0001010010010110011011 |
3 | 1211122120212112200010201201 |
4 | 3030003331101102112123 |
5 | 3314223122214441103 |
6 | 45454030525255031 |
7 | 2645062365612502 |
oct | 314037521222633 |
9 | 54576775603651 |
10 | 14023022421403 |
11 | 4517148639636 |
12 | 16a5909a04477 |
13 | 7a94998636c8 |
14 | 366a09d15839 |
15 | 194b8718b51d |
hex | cc0fd45259b |
14023022421403 has 2 divisors, whose sum is σ = 14023022421404. Its totient is φ = 14023022421402.
The previous prime is 14023022421377. The next prime is 14023022421449. The reversal of 14023022421403 is 30412422032041.
14023022421403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14023022421403 is a prime.
It is not a weakly prime, because it can be changed into another prime (14023022424403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7011511210701 + 7011511210702.
It is an arithmetic number, because the mean of its divisors is an integer number (7011511210702).
Almost surely, 214023022421403 is an apocalyptic number.
14023022421403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14023022421403 is an equidigital number, since it uses as much as digits as its factorization.
14023022421403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 14023022421403 its reverse (30412422032041), we get a palindrome (44435444453444).
The spelling of 14023022421403 in words is "fourteen trillion, twenty-three billion, twenty-two million, four hundred twenty-one thousand, four hundred three".
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