14023042120213 has 4 divisors (see below), whose sum is σ = 16026333851680. Its totient is φ = 12019750388748.

The previous prime is 14023042120163. The next prime is 14023042120229. The reversal of 14023042120213 is 31202124032041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14023042120213 - 2¹⁷ = 14023041989141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14023042120253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1001645865723 + ... + 1001645865736.

It is an arithmetic number, because the mean of its divisors is an integer number (4006583462920).

Almost surely, 2^{14023042120213} is an apocalyptic number.

It is an amenable number.

14023042120213 is a deficient number, since it is larger than the sum of its proper divisors (2003291731467).

14023042120213 is an equidigital number, since it uses as much as digits as its factorization.

14023042120213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2003291731466.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14023042120213 its reverse (31202124032041), we get a palindrome (45225166152254).

The spelling of 14023042120213 in words is "fourteen trillion, twenty-three billion, forty-two million, one hundred twenty thousand, two hundred thirteen".