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14023323321131 is a prime number
BaseRepresentation
bin1100110000010000111100…
…1101001000001100101011
31211122121122111212102120002
43030010033031020030223
53314224231232234011
645454120434453215
72645103011330255
oct314041715101453
954577574772502
1014023323321131
114517292477aa3
1216a599273420b
137a9516cb7b97
14366a37c80cd5
15194ba37c6c3b
hexcc10f34832b

14023323321131 has 2 divisors, whose sum is σ = 14023323321132. Its totient is φ = 14023323321130.

The previous prime is 14023323321121. The next prime is 14023323321157. The reversal of 14023323321131 is 13112332332041.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14023323321131 is a prime.

It is a super-2 number, since 2×140233233211312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14023323321094 and 14023323321103.

It is not a weakly prime, because it can be changed into another prime (14023323321121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7011661660565 + 7011661660566.

It is an arithmetic number, because the mean of its divisors is an integer number (7011661660566).

Almost surely, 214023323321131 is an apocalyptic number.

14023323321131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14023323321131 is an equidigital number, since it uses as much as digits as its factorization.

14023323321131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 14023323321131 its reverse (13112332332041), we get a palindrome (27135655653172).

The spelling of 14023323321131 in words is "fourteen trillion, twenty-three billion, three hundred twenty-three million, three hundred twenty-one thousand, one hundred thirty-one".