14023340121101 has 4 divisors (see below), whose sum is σ = 14130388519104. Its totient is φ = 13916291723100.

The previous prime is 14023340121047. The next prime is 14023340121103. The reversal of 14023340121101 is 10112104332041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14023340121101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14023340121103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53524198805 + ... + 53524199066.

It is an arithmetic number, because the mean of its divisors is an integer number (3532597129776).

Almost surely, 2^{14023340121101} is an apocalyptic number.

It is an amenable number.

14023340121101 is a deficient number, since it is larger than the sum of its proper divisors (107048398003).

14023340121101 is a wasteful number, since it uses less digits than its factorization.

14023340121101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107048398002.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 14023340121101 its reverse (10112104332041), we get a palindrome (24135444453142).

The spelling of 14023340121101 in words is "fourteen trillion, twenty-three billion, three hundred forty million, one hundred twenty-one thousand, one hundred one".