140235006473 has 2 divisors, whose sum is σ = 140235006474. Its totient is φ = 140235006472.

The previous prime is 140235006437. The next prime is 140235006479. The reversal of 140235006473 is 374600532041.

Together with previous prime (140235006437) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113328509449 + 26906497024 = 336643^2 + 164032^2 .

It is a cyclic number.

It is not a de Polignac number, because 140235006473 - 2⁸ = 140235006217 is a prime.

It is not a weakly prime, because it can be changed into another prime (140235006479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70117503236 + 70117503237.

It is an arithmetic number, because the mean of its divisors is an integer number (70117503237).

Almost surely, 2^140235006473 is an apocalyptic number.

It is an amenable number.

140235006473 is a deficient number, since it is larger than the sum of its proper divisors (1).

140235006473 is an equidigital number, since it uses as much as digits as its factorization.

140235006473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 35.

The spelling of 140235006473 in words is "one hundred forty billion, two hundred thirty-five million, six thousand, four hundred seventy-three".