Base | Representation |
---|---|
bin | 11111111000110000101100… |
… | …101001111101000000110011 |
3 | 200101112211000012202011110222 |
4 | 133320300230221331000303 |
5 | 121340143030431004212 |
6 | 1214133213145243255 |
7 | 41353002315042143 |
oct | 3770605451750063 |
9 | 611484005664428 |
10 | 140240021344307 |
11 | 40759505aa9805 |
12 | 1388b55749352b |
13 | 60337673463a1 |
14 | 268b920734923 |
15 | 1132e71261c72 |
hex | 7f8c2ca7d033 |
140240021344307 has 2 divisors, whose sum is σ = 140240021344308. Its totient is φ = 140240021344306.
The previous prime is 140240021344271. The next prime is 140240021344399. The reversal of 140240021344307 is 703443120042041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140240021344307 - 238 = 139965143437363 is a prime.
It is not a weakly prime, because it can be changed into another prime (140240021044307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70120010672153 + 70120010672154.
It is an arithmetic number, because the mean of its divisors is an integer number (70120010672154).
Almost surely, 2140240021344307 is an apocalyptic number.
140240021344307 is a deficient number, since it is larger than the sum of its proper divisors (1).
140240021344307 is an equidigital number, since it uses as much as digits as its factorization.
140240021344307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 140240021344307 its reverse (703443120042041), we get a palindrome (843683141386348).
The spelling of 140240021344307 in words is "one hundred forty trillion, two hundred forty billion, twenty-one million, three hundred forty-four thousand, three hundred seven".
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