Base | Representation |
---|---|
bin | 11111111000110000101101… |
… | …010011110000000110000011 |
3 | 200101112211000222100211211211 |
4 | 133320300231103300012003 |
5 | 121340143041232121233 |
6 | 1214133214220150551 |
7 | 41353002510136144 |
oct | 3770605523600603 |
9 | 611484028324754 |
10 | 140240032301443 |
11 | 40759511202a98 |
12 | 1388b55b098457 |
13 | 60337696b17b9 |
14 | 268b921d87acb |
15 | 1132e721c85cd |
hex | 7f8c2d4f0183 |
140240032301443 has 2 divisors, whose sum is σ = 140240032301444. Its totient is φ = 140240032301442.
The previous prime is 140240032301399. The next prime is 140240032301449. The reversal of 140240032301443 is 344103230042041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140240032301443 is a prime.
It is not a weakly prime, because it can be changed into another prime (140240032301449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70120016150721 + 70120016150722.
It is an arithmetic number, because the mean of its divisors is an integer number (70120016150722).
Almost surely, 2140240032301443 is an apocalyptic number.
140240032301443 is a deficient number, since it is larger than the sum of its proper divisors (1).
140240032301443 is an equidigital number, since it uses as much as digits as its factorization.
140240032301443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 140240032301443 its reverse (344103230042041), we get a palindrome (484343262343484).
The spelling of 140240032301443 in words is "one hundred forty trillion, two hundred forty billion, thirty-two million, three hundred one thousand, four hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.093 sec. • engine limits •