Base | Representation |
---|---|
bin | 1100110000010011111111… |
… | …1000100011101100001111 |
3 | 1211122200202102121122020021 |
4 | 3030010333320203230033 |
5 | 3314232414320343203 |
6 | 45454333451203011 |
7 | 2645132156152141 |
oct | 314047770435417 |
9 | 54580672548207 |
10 | 14024140012303 |
11 | 4517671479183 |
12 | 16a5b80146467 |
13 | 7a96172630b5 |
14 | 366ab4512c91 |
15 | 194c003495bd |
hex | cc13fe23b0f |
14024140012303 has 8 divisors (see below), whose sum is σ = 14524087027680. Its totient is φ = 13525283395680.
The previous prime is 14024140012277. The next prime is 14024140012349. The reversal of 14024140012303 is 30321004142041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14024140012303 - 217 = 14024139881231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14024140012373) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 272573508 + ... + 272624953.
It is an arithmetic number, because the mean of its divisors is an integer number (1815510878460).
Almost surely, 214024140012303 is an apocalyptic number.
14024140012303 is a deficient number, since it is larger than the sum of its proper divisors (499947015377).
14024140012303 is an equidigital number, since it uses as much as digits as its factorization.
14024140012303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 545199377.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14024140012303 its reverse (30321004142041), we get a palindrome (44345144154344).
The spelling of 14024140012303 in words is "fourteen trillion, twenty-four billion, one hundred forty million, twelve thousand, three hundred three".
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